What is the sum of integers from 1 to 100?
5050
The sum of all natural numbers from 1 to 100 is 5050. The total number of natural numbers in this range is 100. So, by applying this value in the formula: S = n/2[2a + (n − 1) × d], we get S=5050.
What is the sum of the integers between 1 and 100 that are divisible by 4?
Numbers which are divisible by 4 between 1 to 100 are : 4 , 8 , 12 ………, 100. => 1300. Hence, The sum of numbers which are divisible by 4 between 1 to 100 is 1300.
How many numbers from 1 to 100 are there each of which is not divisible by 4 but also has 4 as a digit?
7 such
Detailed Solution Therefore, the required numbers are 4, 24, 40, 44, 48, 64, 84. Clearly, there are 7 such numbers. Hence, there are 7 numbers from 1 to 100 each of which is not only exactly divisible by 4 but also has 4 as a digit.
What is the sum of the integers from 1 to 100 that are divisible by 2?
This also forms an A.P. with both the first term and common difference equal to 10. Thus, the sum of the integers from 1 to 100, which are divisible by 2 or 5, is 3050.
What is the sum of the integers from 1 to 100 that are divisible by 2 or 5?
3050
Hence, we have obtained the sum of integers from 1 to 100 which are divisible by 2 or 5 as 3050. Therefore, the correct answer to the question is option (b) 3050.
What is the sum of the numbers from 1 to 100 which are divisible by 6?
16 Numbers are divisible by 6 which lies 1 to 100. Hence, The Sum Of 16 Term which lies 1 to 100 and also divisible by 6 is 816.
What is the sum of the numbers between 1 and 100 which are divisible by 6?
How many numbers are there between 1 and 100 that are not divisible by 3?
There are 65 numbers which are not divisible by 3 between 1 and 100 .
How many numbers from 1 to 100 are there such that each of which is divisible by 8 and whose at least one digit is 8?
There are 4 such numbers from 1 to 100 which when divided by 8 has at least one digit as 8. Those numbers are 8, 48, 80, and 88.
What is the sum of all the numbers between 1 and 1000 which are divisible by 5 but not by 2?
50000
995. Therefore, the sum of all positive integers up to 1000, which are divisible by 5 and not divisible by 2 is 50000. Hence, option (d) is correct.
What is the sum of all natural numbers from 1 to 100 that are divisible by 7?
Here a = 7, d = 7. So solving n = 14. So sum is 735.
What is the divisibility rule of 38?
Divisibility Rules in Short
| Number | Divisible by | Rule |
|---|---|---|
| abcdef | 38 | if ‘abcdef’ is divisible by 2 and 19 |
| abcdef | 39 | if ‘abcdef’ is divisible by 3 and 13 |
| abcdef | 40 | if ‘abcdef’ is divisible by 5 and 8 |
| abcdef | 41 | If ‘abcde-4 ×f’ is divisible by 41 |